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How To Find Average Acceleration From Velocity Time Graph

Completing calculations on curves

You will need to be able to explain and complete calculations on curves in both distance-time and velocity-fourth dimension graphs. This instance uses a velocity-time graph.

A velocity-time graph. The line is split into 4 parts showing different rates of velocity and acceleration.

Look at the graph and explain the motion of the vehicle betwixt 60 and 120 seconds.

  • Look at the vertical \(\text{y}\) -axis. You need to check what blazon of graph it is before you start answering.
  • Between 60 and 85 seconds the graph is curving upwardly. This means that the velocity is increasing at an increasing rate. In other words the vehicle is accelerating non-uniformly.
  • The graph is rising in a reasonably straight line between 85 and 95 seconds. This represents uniform or constant acceleration.
  • In between 95 and 120 seconds the graph is curving to go a horizontal line. This means that the dispatch is becoming less, ie the velocity is increasing at a reducing rate.

If you're sitting the higher tier exam, you might be asked to work out the average acceleration or the altitude travelled over the curved region. To calculate the average acceleration, draw a straight line (shown in dark-green) and find the gradient.

A velocity-time graph. The line is split into 4 parts as before showing different rates of velocity and acceleration. This graph has a second green line in the final stage.

Think, gradient = acceleration.

Acceleration = (15 – 0) ÷ (120 – 60) = 0.25 one thousand/southward 2 .

To find the distance travelled, find the area under the triangle made by the greenish line.

Altitude travelled (area nether line) = ½ × (120 – 60) × 15 = 450 chiliad

Source: https://www.bbc.co.uk/bitesize/guides/z29dqty/revision/5

Posted by: barnardusionswut.blogspot.com

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